The product of zeroes of a cubic polynomial x3-3 x2-x-5 isA- 5B- -5C- 3D- -1

The correct option is B 5If α, β and γ are the nbsp;the zeroes of a cubic polynomial nbsp; ax^3+bx^2+cx+d , then αβγ = d/a Given polynomial: x^3 3x^2 x+5 ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard X

Mathematics

Relationship between Zeroes and Coefficients of a Polynomial

The product o...

Question

The product of zeroes of a cubic polynomial $x^{3} - 3 x^{2} - x + 5$ is

No worries! We‘ve got your back. Try BYJU‘S free classes today!

-5

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

No worries! We‘ve got your back. Try BYJU‘S free classes today!

-1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B -5
If $α$ , $β$ and $γ$ are the the zeroes of a cubic polynomial $a x^{3} + b x^{2} + c x + d$ ,
then
$α$ $β$ $γ$ $= \frac{- d}{a}$
Given polynomial: $x^{3} - 3 x^{2} - x + 5$
$∴$ Product of zeroes is $\frac{- 5}{1}$ = -5.

Suggest Corrections

Similar questions

Q. The product of zeroes of a cubic polynomial

x^{3} - 3 x^{2} - x + 5

Q. The polynomial which when divided by −x² + x − 1 gives a quotient x − 2 and remainder 3, is

(a) x³ − 3x² + 3x − 5
(b) −x³ − 3x² − 3x − 5
(c) −x³ + 3x² − 3x + 5
(d) x³ − 3x² − 3x + 5

Q. The number of zeroes, the polynomial

x^{7} + x^{5} + x^{3} + x + 1

can have is equal to .

Q. The zero of the polynomial (

x - 5

) occurs at

x

Sum of zeroes of the polynomial $x^{2} - 25$ is

Join BYJU'S Learning Program

The product of zeroes of a cubic polynomial x3−3x2−x+5 is

The correct option is B -5If α, β and γ are the the zeroes of a cubic polynomial ax3+bx2+cx+d , then αβγ =−da Given polynomial: x3−3x2−x+5 ∴ Product of zeroes is −51 = -5.

The product of zeroes of a cubic polynomial $x^{3} - 3 x^{2} - x + 5$ is

The correct option is B -5
If $α$ , $β$ and $γ$ are the the zeroes of a cubic polynomial $a x^{3} + b x^{2} + c x + d$ ,
then
$α$ $β$ $γ$ $= \frac{- d}{a}$
Given polynomial: $x^{3} - 3 x^{2} - x + 5$
$∴$ Product of zeroes is $\frac{- 5}{1}$ = -5.