The product(s) when dichlorine hexoxide reacts with $N a O H$ is(are):

$N a C l O_{4}$

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$N a O C l$

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$N a C l O_{2}$

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$N a C l O_{3}$

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Solution

The correct option is D
$N a C l O_{3}$

In the gaseous state, the formula $C l_{2} O_{6}$ is accurate but in the liquid (red) and solid states, the compound exists as chloryl chlorate - $[C l O_{2}^{+}] [C l O_{4}^{-}]$ . strangely, it is not a dimer of the other chlorine oxide - $C l O_{3}$ . At room temperature, it is a dark red fuming liquid that crystallizes into a red ionic solid.

$C l_{2} O_{6} + 2 N a O H ⟶ N a C l O_{4} + N a C l O_{3} + H_{2} O$

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