Question

The production of saleable steel in some of the steel plants of our country during 1999 is given below:

Plant	Bhilai	Durgapur	Rourkela	Bokaro
Production (in thousand tonnes)	160	80	200	150

Construct a bar graph to represent the above data on a graph paper by using the scale 1 big divisions = 20 thousand tonnes.

Answer 1

Let's draw two mutually perpendicular lines OX and OY.
Along the horizontal line OX, let's mark plants; and along the vertical line OY, let's mark the production.
Along the axis OX, let's measure an equal width for each bar, the gap between the bars being the same.
We will now choose a suitable scale to determine the heights of the bar.
Here, let's choose 1 big division = 20 thousand tonnes
Therefore, the heights of the bars as follows:
Height of the bar against Bhilai $=\frac{160}{20}=8$ units.
Height of the bar against Durgapur $=\frac{80}{20}=4$ units.
Height of the bar against Rourkela $=\frac{200}{20}=10$ units.
Height of the bar against Bokaro $=\frac{150}{20}=7.5$ units.
Now, based on the above calculation the graph is as follows: