The products (a) and (b) are :

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Solution

The correct option is C
$L A H$ reduces both ester (here , cyclic ester) and ketone group to alcohols, whereas $N a B H_{4}$ reduces only ketone
group to alcohol.

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(A)

(B)

H_{2} / N i \leftarrow --- - P h N O_{2} L A H - -- \to

(B) N a B H_{4} \leftarrow --- - C H_{3} N_{3} L A H - -- \to (A)

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