The products "A" and "B" formed in above reactions are:

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A
Dehydration occurs through carbocation intermediate and the product formed will be Saytzeff's alkene.

Since potassium tert-butoxide is a bulkier base, it will abstract the proton from less hindered side producing Hofmann's alkene.

Suggest Corrections

Similar questions

(x)

(y)

P e n t a n - 2 - o n e N H_{2} O H - ---- \to N H_{3} C l [A] T s C l - -- \to H_{2} O - - \to p r o d u c t

Join BYJU'S Learning Program