You visited us 1 times! Enjoying our articles? Unlock Full Access!

Preparations and Uses of Caustic Soda

The products ...

Question

The products obtained when chlorine gas reacts with cold and dilute aqueous $N a O H$ are:

C l O^{-}

and

C l O_{3}^{-}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C l O_{2}^{-}

and

C l O_{3}^{-}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C l^{-}

and

C l O^{-}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

C l^{-}

and

C l O_{2}^{-}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $C l^{-}$ and $C l O^{-}$
Case -1: Hot Concentrated NaOH
The reaction between chlorine and hot concentrated sodium hydroxide solution is:
$N a O H + C l_{2} \to 5 N a C l + N a C l O_{3} + 3 H_{2} O$
Case -2:Cold NaOH
The reaction between chlorine and cold dilute sodium hydroxide solution is:
$2 N a O H + C l_{2} \to N a C l + N a C l O + H_{2} O$

Suggest Corrections

Similar questions

N a O H

3 C l O^{-} ⟶ C l O_{2}^{-} + 2 {C l}^{-}

C l O^{-} + C l O^{-} K_{1} - \to C l O_{2}^{-} + {C l}^{-}

C l O_{2}^{-} + C l O^{-} K_{2} - \to C l O_{3}^{-} + {C l}^{-}

3 C l O^{-} \to C l O_{3}^{-} + 2 C l

C l O^{-} + C l O^{-} K_{1} - \to C l O_{2}^{-} + C l^{-}

C l O_{2}^{+} C l O^{-} k_{2} - \to C l O_{3}^{-} + C l^{-}

3 C l O^{-} \to C l O_{3}^{-} + 2 C l^{-}

C l O^{-} + C l O^{-} \to C l O_{2}^{-} + C l^{-} - - - - (s l o w)

C l O_{2}^{-} + C l O^{-} \to C l O_{3}^{-} + C l^{-} - - - - - (f a s t)

C l - O

C l O^{-}, C l O_{2}^{-}, C l O_{3}^{-}

C l O_{4}^{-}

Join BYJU'S Learning Program