The products of combustion of an aliphatic thiol (RSH) at 298 K are:

C O_{2} (g), H_{2} O (g), a n d S O_{2} (g)

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C O_{2} (g), H_{2} O (l), a n d S O_{2} (g)

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C O_{2} (l), H_{2} O (l), a n d S O_{2} (g)

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C O_{2} (l), H_{2} O (l), a n d S O_{2} (l)

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Solution

The correct option is B $C O_{2} (g), H_{2} O (l), a n d S O_{2} (g)$
$R S H, e . g ., C H_{3} S H + 3 O_{2} (g) \to C O_{2} (g) + S O_{2} (g) + 2 H_{2} O (l) .$

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Similar questions

298 K

{Na}_{2} {CO}_{3} (aq) + H_{2} {SO}_{4} (aq) \to ?

C H_{3} O H (l)

C H_{3} O H (l) + \frac{3}{2} O_{2} (g) \to C O_{2} (g) + 2 H_{2} O (l); △_{r} H^{⊖} = - 726 k J

C (s) + O_{2} (g) \to C O_{2} (g), Δ H = - 394 k J

H_{2} (g) + \frac{1}{2} O_{2} (g) \to H_{2} O (l), Δ H = - 286 k J

{C H}_{3} O H (l)

{C H}_{3} O H (l) + \frac{3}{2} O_{2} (g) ⟶ C O_{2} (g) + 2 H_{2} O (l); Δ H = - 726 k J

C (s) + O_{2} (g) ⟶ C O_{2} (g); Δ H = - 394 k J

H_{2} (g) + \frac{1}{2} O_{2} (g) ⟶ H_{2} O (l); Δ H = - 286 k J

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