The products of electrolysis of dilute aqueous solution of sodium hydride are :

N a

at cathode and

H_{2}

at anode

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H_{2}

at cathode and

O_{2}

at cathode

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N a

at cathode and

O_{2}

at anode

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H_{2}

at both cathode and anode

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Solution

The correct option is B $H_{2}$ at both cathode and anode
Electrolyte dissociates as $N a^{+}$ and $H^{-}$ ions along with $H^{+}$ and $O H^{-}$ ions in the solution.
At cathode (reduction) - $2 H^{+} + 2 e^{-} \to H_{2}$
At anode (oxidation) - $2 H^{-} \to H_{2}$ + $2 e^{-}$
Hence, hydrogen is produced at both cathode and anode.

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Aqueous $C u S O_{4}$ is electrolyzed using $A g$ as anode and $C u$ as cathode, then product of electrolysis at anode and cathode are, respectively

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Which of the following statements are correct?

a) The electrolysis of aqueous NaCl produces hydrogen gas at the cathode and chlorine gas at the anode .

b) The electrolysis of a $C u S O_{4}$ solution using Pt electrodes causes the liberation of $O_{2}$ at the anode and the deposition of copper at the cathode .

c) Oxygen and hydrogen are produced at the anode and cathode during the electrolysis of dilute aqueous solution of $H_{2} S O_{4}$ .

d) All electrolytic reactions are redox reactions .

Q. In electrolysis of dilute solution of

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, products formed at cathode and at anode are

respectively :

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The products of electrolysis of dilute aqueous solution of sodium hydride are :

The correct option is B H2 at both cathode and anodeElectrolyte dissociates as Na+ and H− ions along with H+ and OH− ions in the solution. At cathode (reduction) - 2H++2e−→H2At anode (oxidation) - 2H−→H2 + 2e−Hence, hydrogen is produced at both cathode and anode.