The products of the hydrolysis of $P {C l}_{3}$ are :

H C l, H_{3} P O_{4}

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H C l, H_{3} P O_{3}

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{C l}_{2}, H_{3} P O_{3}

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H C l, P O {C l}_{3}, H_{3} P O_{4}

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Solution

The correct option is B $H C l, H_{3} P O_{3}$
Hydrolysis of $P C l_{3}$ gives:
$2 P C l_{3} + 6 H_{2} O \to 2 H_{3} P O_{3} + 6 H +$

$P C l_{3} + 3 H_{2} O \to H_{3} P O_{3} + 3 H +$

Option B is correct.

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Similar questions

Q. The product formed by complete hydrolysis of

P C l_{3}

are: -

Q. The order of the oxidation state of the phosphorous atom in

H_{3} P O_{2}, H_{3} P O_{4}, H_{3} P O_{3}

, and

H_{4} P_{2} O_{6}

Q. On hydrolysis of

P_{4} O_{10}

with water we obtain:

Q. For

H_{3} P O_{3} a n d H_{3} P O_{4}

, the correct choice is

1 mole of how many of the following acids neutralize exactly one mole of NaOH, under required favorable conditions? $H C l, H N O_{3}, H_{2} S O_{4}, H_{2} S O_{3}, H_{3} P O_{4}, H_{3} P O_{3}, H_{3} P O_{2}, H_{4} P_{2} O_{5}, H_{3} B O_{3}$ ___

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The products of the hydrolysis of PCl3 are :

The correct option is B HCl, H3PO3 Hydrolysis of PCl3 gives:2PCl3+6H2O→2H3PO3+6H+PCl3+3H2O→H3PO3+3H+Option B is correct.

The products of the hydrolysis of $P {C l}_{3}$ are :

The correct option is B $H C l, H_{3} P O_{3}$
Hydrolysis of $P C l_{3}$ gives:
$2 P C l_{3} + 6 H_{2} O \to 2 H_{3} P O_{3} + 6 H +$

$P C l_{3} + 3 H_{2} O \to H_{3} P O_{3} + 3 H +$

Option B is correct.