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Question

The products of the reaction between C6H5NH2,CHCl3 and KOH are:

A
C6H5Cl+NH4Cl+KCl
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B
C6H5CN+KCl+H2O
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C
C6H5NC+KCl+H2O
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D
C6H5OH+NH4Cl+H2O
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Solution

The correct option is C C6H5NC+KCl+H2O
The products of the reaction between C6H5NH2,CHCl3 and KOH are C6H5NC+KCl+H2O.

C6H5NH2+CHCl3+3KOHΔC6H5NC+3KCl+3H2O

It is an example of Hoffmann's carbylamine test/isocyanide test.

Aliphatic or aromatic primary amines on heating with chloroform and alcoholic KOH give foul smelling alkyl isocyanides or carbylamines.

Secondary or tertiary amines do not give this test.

Option C is correct.

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