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Question

The projection of the line x+11=y2=z13 on the plane x – 2y + z = 6 is the line of intersection of this plane with the plane

A
2x + y + 2 = 0
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B
3x + y – z = 2
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C
2x – 3y + 8z = 3
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D
2x - y + 2 = 0
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Solution

The correct option is A 2x + y + 2 = 0
Equation of plane through (–1, 0, 1) is
a(x + 1) + b(y – 0) + c(z – 1) = 0 . . . .(i)
Which is parallel to given line and perpendicular to given plane

– a + 2b + 3c = 0 . . . .(ii)
and a – 2b + c = 0 . . . .(iii)
From Eqs. (ii) and (iii), c = 0, a = 2b
From Eqs. (i), 2b(x + 1) + by = 0
2x + y + 2 = 0

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