The properties of mercury at 300 K are - Density-13529 Kg-m3- Cp-0-1393 kJ-kgK- dynamic viscosity -0-1523-10-2 Ns-m2 and thermal conductivity -8-540 W-mK- The Prandtl number of the mercury at 300 K is

Given data: ρ=13529 Kg/m^3 C_P=0.1393 kJ/kgK =139.3 J/kgK μ=0.1523×10^ 2 Ns/m^2 k_f=8.540 W/mK Prandtl number, P_γ=μ C_Pk_f=0.1523×10^ 2×139.38.540 nb ...

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Standard XII

Chemistry

Longest Chain Rule

The propertie...

Question

The properties of mercury at $300 K$ are : $D e n s i t y = 13529 K g / m^{3}, C_{p} = 0.1393 k J / k g K,$ dynamic viscosity $= 0.1523 \times 10^{- 2} N s / m^{2}$ and thermal conductivity $= 8.540 W / m K .$ The Prandtl number of the mercury at $300 K$ is

0.0248

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Solution

The correct option is A
$0.0248$
Given data:
$ρ = 13529 K g / m^{3} C_{P} = 0.1393 k J / k g K = 139.3 J / k g K μ = 0.1523 \times 10^{- 2} N s / m^{2} k_{f} = 8.540 W / m K$

Prandtl number,
$P_{γ} = \frac{μ C_{P}}{k_{f}} = \frac{0.1523 \times 10^{- 2} \times 139.3}{8.540}$

$= 0.0248$

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The properties of mercury at 300 K are : Density=13529 Kg/m3, Cp=0.1393 kJ/kgK, dynamic viscosity =0.1523×10−2 Ns/m2 and thermal conductivity =8.540 W/mK. The Prandtl number of the mercury at 300 K is

The correct option is A 0.0248Given data: ρ=13529 Kg/m3CP=0.1393 kJ/kgK =139.3 J/kgKμ=0.1523×10−2 Ns/m2kf=8.540 W/mK Prandtl number, Pγ=μCPkf=0.1523×10−2×139.38.540 =0.0248

The properties of mercury at $300 K$ are : $D e n s i t y = 13529 K g / m^{3}, C_{p} = 0.1393 k J / k g K,$ dynamic viscosity $= 0.1523 \times 10^{- 2} N s / m^{2}$ and thermal conductivity $= 8.540 W / m K .$ The Prandtl number of the mercury at $300 K$ is

The correct option is A
$0.0248$
Given data:
$ρ = 13529 K g / m^{3} C_{P} = 0.1393 k J / k g K = 139.3 J / k g K μ = 0.1523 \times 10^{- 2} N s / m^{2} k_{f} = 8.540 W / m K$

Prandtl number,
$P_{γ} = \frac{μ C_{P}}{k_{f}} = \frac{0.1523 \times 10^{- 2} \times 139.3}{8.540}$

$= 0.0248$