1
Question
The proposition p→∼(p∧∼q) is equivalent to
The proposition p→∼(p∧∼q) is equivalent to
Open in App
Solution
The correct option is D (∼p)∨q
p→∼(p∧∼q)
=∼p ∨∼(p∧∼q)
=∼p ∨(∼p∨q)
=∼p∨q
p→∼(p∧∼q)
=∼p ∨∼(p∧∼q)
=∼p ∨(∼p∨q)
=∼p∨q
Suggest Corrections
0
Similar questions
View More
Join BYJU'S Learning Program
Explore more
Join BYJU'S Learning Program
