334
Question
The proposition p→∼(p∧∼q) is equivalent to
The proposition p→∼(p∧∼q) is equivalent to
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Solution
The correct option is D (∼p)∨q
p→∼(p∧∼q)
=∼p ∨∼(p∧∼q)
=∼p ∨(∼p∨q)
=∼p∨q
p→∼(p∧∼q)
=∼p ∨∼(p∧∼q)
=∼p ∨(∼p∨q)
=∼p∨q
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