Question

The proposition $(p\Rightarrow \sim p)\wedge (\sim p\Rightarrow p)$ is :

• A. a tautology
• B. a contradiction
• C. neither a tautology nor a contradiction
• D. logically equivalent to $x\vee (\sim x)$

Answer 1

The correct option is B a contradiction

$p$	$\sim p$	$a=(p\Rightarrow \sim p)$	$b=(\sim p\Rightarrow p)$	$a\wedge b$
$T$	$F$	$F$	$T$	$F$
$F$	$T$	$T$	$F$	$F$

$\therefore (p\Rightarrow \sim p)\wedge (\sim p\Rightarrow p)$ is always false . so, its a contradiction.