The proposition p - p - q A- either 1 or 2B- neither 1 or 2C- a contradictionD- a tautology

The correct option is B neither (1) or (2) p →∼ (p∧∼ q) is neither contradiction nor tautology ...

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Contra-Positive

The propositi...

Question

The proposition $p \to\sim (p \land \sim q)$

a contradiction

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a tautology

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either (1) or (2)

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neither (1) or (2)

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