The proposition - p - p- q is equivalent to-

The correct option is B p→∼ q (∼ p)∨ (p∧∼ q) p q ∼ p ∼ q p∧∼ q (∼ p)∨ (p∧∼ q) #160; #160; #160; p→∼ q T ...

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Direct Method of Validation

The propositi...

Question

The proposition $(\sim p) \lor (p \land \sim q)$ is equivalent to.

p \to\sim q

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p \lor \sim q

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q \to p

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p \land \sim q

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Solution

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Similar questions

\sim (p \Leftrightarrow q)

\sim (p \lor \sim q) \lor \sim (p \lor q)

\sim (p \lor \sim q) \lor \sim (p \lor q)

p \lor (\sim p \lor q)

p \lor (\sim p \land q)

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