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Standard XII

Physics

Magnetic Field Due to a Circular Ring on the Axis

The prototype...

Question

The prototype shows that magnetic field cannot be kept constant in a wide range of 3 m. Therefore you reduce the length of the bar to 0.2 m keeping all other remaining parameter unchanged. What is the power exerted?

1 W

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1/25 W

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1/9 W

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5 W

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Solution

The correct option is D 1/9 W
$P = \frac{(B l v)^{2}}{0.9}$

$= \frac{(0.25 \times 0.2 \times 2)^{2}}{0.9} = \frac{(.1)^{2}}{.09}$

$= 1 / 9 W$

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The prototype shows that magnetic field cannot be kept constant in a wide range of 3 m. Therefore you reduce the length of the bar to 0.2 m keeping all other remaining parameter unchanged. What is the power exerted?

The correct option is D 1/9 WP=(Blv)20.9=(0.25×0.2×2)20.9=(.1)2.09=1/9W

The correct option is D 1/9 W
$P = \frac{(B l v)^{2}}{0.9}$

$= \frac{(0.25 \times 0.2 \times 2)^{2}}{0.9} = \frac{(.1)^{2}}{.09}$

$= 1 / 9 W$