The Prussian blue colour obtained during the test of nitrogen by Lassaigne's test is due to the formation of ?

F e_{4} [F e (C N)_{6}]_{3}

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F e_{2} [F e (C N)_{6}]

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F e_{3} [F e (C N)_{6}]_{4}

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N a_{4} [F e (C N)_{6}]

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Solution

The correct option is A $F e_{4} [F e (C N)_{6}]_{3}$
Reaction of process:
$F e^{3 +} + [F e C N)_{6}]^{4 -} ⟶ F e_{4} [F e (C N)_{6}]_{3}$
Prussian blue
(Ferri-ferrocyanide)

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Similar questions

In the Lassaigne’s test for nitrogen in an organic compound, the Prussian blue colour is obtained due to the formation of:

(a) Na₄[Fe(CN)₆] (b) Fe₄[Fe(CN)₆]₃ (c) Fe₂[Fe(CN)₆] (d) Fe₃[Fe(CN)₆]₄

{N H}_{2} - {N H}_{2}

{F e}_{4} {[F e ({C N}_{6})]}_{3}

F e {S o}_{4}, F e {C I}_{3}

{F e}^{2 +}

K_{3} [{F e (C N)}_{6}]

{F e}^{3 +}

K_{4} [{F e (C N)}_{6}]

K_{4} [F e (C N)_{6}]

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