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Question

The pth, qth and rth terms of an A.P. are a, b, c respectively. Show that

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Solution

Let t and d be the first term and the common difference of the A.P. respectively.

The nth term of an A.P. is given by, an = t + (n1) d

Therefore,

ap = t + (p1) d = a … (1)

aq = t + (q1)d = b … (2)

ar = t + (r1) d = c … (3)

Subtracting equation (2) from (1), we obtain

(p – 1 – q + 1) d = ab

⇒ (pq) d = a b

Subtracting equation (3) from (2), we obtain

(q – 1 – r + 1) d = bc

⇒ (q r) d = b c

Equating both the values of d obtained in (4) and (5), we obtain

Thus, the given result is proved.


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