You visited us 4 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Physics

Variation of G Due to Height and Depth

The pulley ar...

Question

The pulley arrangements shown in figure are identical, the mass of the rope being negligible. In case I, the mass m is lifted by attaching a mass 2m to the other end of the rope. In case II, the mass m is lifted by pulling the other end of the rope with a constant downward force F = 2mg, where g is acceleration due to gravity. The acceleration of mass in case I is:

Zero

No worries! We‘ve got your back. Try BYJU‘S free classes today!

More then that in case II

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Less than that in case II

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Equal to that in case II

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B Less than that in case II
Case-1 :
Acceleration of mass $m$ is, $a_{1} = \frac{2 m g - m g}{m + 2 m} = \frac{g}{3}$

Case-2:
Acceleration of mass $m$ is, $a_{2} = \frac{F}{m} = \frac{2 m g}{m} = 2 g$

So, $a_{1} < a_{2}$
Option C is correct.

Suggest Corrections

Similar questions

Q. Two pulley arrangements of figure given are identical. The mass of the rope in negligible. In fig(a), the mass

m

is lifted by attaching a mass

2 m

to the other end of the rope. In fig(b),

m

is lifted up by pulling the other end of the rope with a constant downward force

F = 2 m g

. The acceleration of

m

in the two cases are respectively

Q. The two pulley arrangements shown in the figure are identical. The mass of the rope is negligible. In (a) the mass

m

is lifted up by attaching a mass

2 m

to the other end of the rope. In (b)

m

is lifted up by pulling the order end of the rope with a constant downward force of

2 m g

. The ratio of acceleration in two cases will be

Q. Two pulley arrangements of figure given are identical. The mass of the rope in negligible. In fig(a), the mass

m

is lifted by attaching a mass

2 m

to the other end of the rope. In fig(b),

m

is lifted up by pulling the other end of the rope with a constant downward force

F = 2 m g

. The acceleration of

m

in the two cases are respectively

The pulley arrangements of figures (a) and (b) are identical. The mass of the rope is negligible. In Fig. (a), the mass m is lifted up by attaching a mass 2m to the other end of the rope. In Fig. (b) , m is lifted up by pulling the other end of the rope with a constant downward force F=2mg. The acceleration of m is the same in both cases.

Q. The pulley in arrangements in Fig. (a) and Fig. (b) are identical. The mass of the rope is negligible. In Fig (a), the mass m is lifted up by attaching a mass 2 m to the other end of the rope. In (b), m is lifted up by pulling the other end of the rope with a constant downwards force F = 2mg. The acceleration of m is the same in both cases.

Join BYJU'S Learning Program

The correct option is B Less than that in case IICase-1 :Acceleration of mass m is, a1=2mg−mgm+2m=g3Case-2:Acceleration of mass m is, a2=Fm=2mgm=2gSo, a1<a2Option C is correct.

The correct option is B Less than that in case II
Case-1 :
Acceleration of mass $m$ is, $a_{1} = \frac{2 m g - m g}{m + 2 m} = \frac{g}{3}$

Case-2:
Acceleration of mass $m$ is, $a_{2} = \frac{F}{m} = \frac{2 m g}{m} = 2 g$

So, $a_{1} < a_{2}$
Option C is correct.