The pulley system drawn lifts a load of $150$ N when an effort of $60$ N is applied. Find its mechanical advantage.

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Solution

Load to be lifted $F_{L} = 150 N$
Effort required $F_{E} = 60 N$
Mechanical advantage $M A = \frac{F_{L}}{F_{E}} = \frac{150}{60} = 2.5$

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The pulley system drawn lifts a load of 150N when an effort of 60N is applied. Find its mechanical advantage.

Load to be lifted FL=150 NEffort required FE=60 NMechanical advantage MA=FLFE=15060=2.5

The pulley system drawn lifts a load of $150$ N when an effort of $60$ N is applied. Find its mechanical advantage.

Load to be lifted $F_{L} = 150 N$
Effort required $F_{E} = 60 N$
Mechanical advantage $M A = \frac{F_{L}}{F_{E}} = \frac{150}{60} = 2.5$