Question

The pulleys and strings shown in the figure are smooth and a negligible mass. For the system to remain in equilibrium, find the angle $\theta$.

Answer 1

For block A, T-mg= m(0)

For block B, T-mg= m(0)

(Since the both A and B blocks are similar and tension in the strings are mg. It has zero acceleration, as system is in equilibrium).

So, $2Tcos\theta =\sqrt{2}mg$

2mgCos$\theta$= $\sqrt{2}mg$

$\theta ={45}^o$