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Question

The pulleys in figure (10-E6) are identical, each having a radius R and moment of inertia I. Find the acceleration of the block M.

Figure

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Solution

Free the body diagram of the system,



For block of mass M,
Mg-T1=Ma ... (i)
T1-T2 R=Iαusing, a=αrT1-T2=IaR2 ... (ii) For pully 1Similarly, T2-T3=IaR2 ... (iii) For pully 2

For block of mass m,
T3-mg=ma ...(iv) For block m

Adding equations (ii) and (iii), we get:
T1-T3=2IaR2 ...(v)
Adding equations (i) and (iv), we get:
-mg+Mg+T3-T1=Ma+ma ...(vi)
Using equations (v) and (vi), we get:
Mg-mg = Ma+ma+2IaR2a=M-mgM+m+2IR2

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