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Mechanism of Adsorption

The purity of...

Question

The purity of $H_{2} O_{2}$ in a given sample is $85 %$ . Calculate the weight of impure sample of $H_{2} O_{2}$ which requires $10$ mL of $\frac{M}{5} K M n O_{4}$ solution in a titration in acidic medium.

2

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0.2

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0.17

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0.15

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Solution

The correct option is B $0.2$ g
Milliequivalents of $M n O_{4}^{⊝} \equiv$ Milliequivalents of $H_{2} O_{2}$
$10 \times \frac{M}{5} \times 5 \equiv$ Milliequivalents of $H_{2} O_{2}$
$\Rightarrow 10$ Milliequivalents $\equiv$ Milliequivalents of $H_{2} O_{2}$
Weight of $H_{2} O_{2} = 10 \times 10^{- 3} \times \frac{34}{2} = 0.17$ g
Weight of impure $H_{2} O_{2} = \frac{100}{85} \times 0.17 = 0.2$ g

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