The quadrantal bearings of the lines AB and CA are S 30-E and S 70- E- The included angle CAB is

(∠ CAB=140) F.B of line AB = 180^∘ 30^∘=150^∘ B.B of line CA= 360^∘ 70^∘=290^∘ ∠ CAB =F.B of AB B.B of CA =150^∘ 290^∘= 140^∘ ∠ CAB = 140^∘+360^∘=220^∘ ...

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Standard XII

Mathematics

Sign of Trigonometric Ratios in Different Quadrants

The quadranta...

Question

The quadrantal bearings of the lines AB and CA are $S 30^{\circ} E a n d S 70^{\circ} E$ . The included angle CAB is
220

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Solution

The correct option is A 220
$(∠ C A B = 140)$

$F.B of line AB = 180^{\circ} - 30^{\circ} = 150^{\circ}$

$B.B of line CA = 360^{\circ} - 70^{\circ} = 290^{\circ}$

$∠ C A B = F.B of AB - B.B of CA$

$= 150^{\circ} - 290^{\circ} = - 140^{\circ}$

$∠ C A B = - 140^{\circ} + 360^{\circ} = 220^{\circ}$

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The quadrantal bearings of the lines AB and CA are S30∘E and S70∘E. The included angle CAB is220

The correct option is A 220(∠CAB=140) F.B of line AB=180∘−30∘=150∘ B.B of line CA=360∘−70∘=290∘ ∠CAB=F.B of AB−B.B of CA =150∘−290∘=−140∘ ∠CAB=−140∘+360∘=220∘

The quadrantal bearings of the lines AB and CA are $S 30^{\circ} E a n d S 70^{\circ} E$ . The included angle CAB is
220