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Question

The quadratic equation having roots 2p and 2q is:

A
x2 – 3x + 4 = 0
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B
x2 – 6x - 8 = 0
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C
x2 – 6x +4 = 0
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D
x2 – 6x + 8 = 0
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E
4x2 – 6x + 4 = 0
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Solution

The correct option is D x2 – 6x + 8 = 0

Soln:

Substitute x by( x2)

The equation becomes: (x2)23(x2)+2=0, x26x+8=0. Hence option (d).


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