Question

The quadratic equation having roots as$p+2$and$q+2$ is:

• A. x² – x = 0
• B. x² – 7x + 12 = 0
• C. x² – 7x – 12 = 0
• D. x² + 7x + 12 = 0
• E. x² + x = 0

Answer 1

The correct option is B x² – 7x + 12 = 0

Soln:
Substitute x by (x-2)
The equation becomes:$(x-2{)}^2-3(x-2)+2=0,x^2-7x+12=0.$Hence option (b).

2nd option: From given equation $p+q=3$then$(p+2)+(q+2)=7$thus either option b or c.

Now,$p\times q=2$(i.e.,)$1\times 2or2\times 1.$In both sides if we increase both roots by 2 then it will be $3\times 4or4\times 3$(i.e.,)12.Option (b)