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Byju's Answer
Standard X
Mathematics
Quadratic Equations
The quadratic...
Question
The quadratic equation whose one root is
(
3
+
2
3
)
is
(a)
x
2
+
6
x
-
3
=
0
(b)
x
2
-
6
x
-
3
=
0
(c)
x
2
+
6
x
+
3
=
0
(d)
x
2
-
6
x
+
3
=
0
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Solution
(b)
x
2
-
6
x
-
3
=
0
It is given that one root of the equation is
(
3
+
2
3
)
.
Therefore, the other root will be
(
3
−
2
3
)
.
∴
α
+
β
=
6
and
α
β
=
(
3
+
2
3
)
(
3
−
2
3
)
=
9
−
12
=
−
3
Therefore
,
the
r
equired equation is {
x
2
−
6
x
+
(
−
3
)
=
0
}
.
⇒
x
2
−
6
x
−
3
=
0
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0
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Q.
If the sum of the roots of a quadratic equation is 6 and their product is 6, the equation is
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