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Question

The quadratic equation whose roots are α2+αβ & β2+αβis:

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Solution

Consider the given roots.
α2+αβ and β2+αβ

We know that
x2(sum of roots)x+product of roots=0

x2(α2+αβ+β2+αβ)x+(α2+αβ)(β2+αβ)=0

x2(α2+β2+2αβ)x+(α2+αβ)(β2+αβ)=0

Hence, this is the answer.

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