The quadratic equation whose roots are real and equal is:

3x² - 5x + 2 = 0

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2x² - 4x + 3 = 0

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x² - 4x + 4 = 0

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x² - 2√2 - 6 = 0

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Solution

The correct option is C
x² - 4x + 4 = 0

Consider the equation x ² - 4x + 4 = 0
x ² - 4x + 4 = 0

(x-2)²=0

x=2

Thus the roots of the equation x ² - 4x + 4 = 0 are equal and real.

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Similar questions

\frac{\sqrt{5}}{3}, - \sqrt{5}

3 x^{2} + 2 \sqrt{5 x} - 5 = 0

1

\frac{2}{3}

3 x^{2}

α

β

3 x^{2} - 4 x + 1 = 0

\frac{α^{2}}{β}

\frac{β^{2}}{α}

Δ (x) = ∣ ∣ ∣ ∣ \begin{matrix} 6 - 5 x & x - 2 & 4 - 4 x x - 2 & 2 - x & 0 4 - 4 x & 0 & 3 - 5 x \end{matrix} ∣ ∣ ∣ ∣ = 0

\geq

\frac{x^{2} - 5 x + 12}{5 x - 12} = \frac{x^{2} - x - 4}{x + 4}

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