CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The quadratic equation whose roots are the sum and difference of the squares of roots of the equation x23x+2=0 is

A
x2+8x+15=0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
x28x15=0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
x2+8x15=0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
x28x+15=0
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D x28x+15=0
Given equation is x23x+2=0
(x2)(x1)=0
x=1,2
Therefore, the roots of the equation are 1 and 2.
Sum of the squares of the roots 1+4=5
Difference of the squares of the roots 41=3
Hence, the roots of the new equation are 5 and 3.
Therefore, the new quadratic equation is x28x+15=0
[ sum5+3=8 and product(5)(3)=15]

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Solving QE by Factorisation
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon