The quadratic expression ax2+bx+c>0∀xϵR, then which of the following option(s) is/are correct ?
A
13a–5b+2c>0
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B
13a–b+2c>0
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C
c>0,D<0
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D
a+c>b,D<0
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Solution
The correct options are A13a–5b+2c>0 B13a–b+2c>0 Cc>0,D<0 Da+c>b,D<0 ax2+bx+c>0∀xϵR⇒a>0,D<0f(0)=c>0f(−1)=a−b+c>0⇒a+c>bf(−3)+f(−2)=13a−5b+2c>0f(−3)+f(2)=13a−b+2c>0