Question

The Quadratic $kx(x-2)+6=0$ has 2 equal roots. Find the value of $k$.

Answer 1

Given,

$kx(x-2)+6=0$

$k{x}^2-2kx+6=0$

Since the roots are equal,

$\Rightarrow b^2=4ac$

$(-2k{)}^2=4(k\left)\right(6)$

$4k^2=4k\left(6\right)$

$\therefore k=6$