Question

The quadrilateral ABCD given below is a parallelogram. Find the values of y .

• A. 45°
• B. 65°
• C. 75°
• D. 80°

Answer 1

The correct option is C

75°

$(3x-10{)}^{\circ }$ = $(x+80{)}^{\circ }$ (opposite angles of a parallelogram)

2x = ${90}^{\circ }$

x = ${45}^{\circ }$

$(3x-10{)}^{\circ }$ + $(y+25{)}^{\circ }$ = ${180}^{\circ }$ (Adjacent angles of a parallelogram)

${80}^{\circ }$+ y + ${25}^{\circ }$ = ${180}^{\circ }$

y = ${180}^{\circ }$ – ${80}^{\circ }$ - ${25}^{\circ }$

= ${75}^{\circ }$