Question

The quantity $\frac{PV}{k_{B}T}$ represents the:

$(k_B$: Boltzmann constant)

• A. number of particle of the gas
• B. mass of the gas
• C. number of the moles of the gas
• D. translation energy of the gas

Answer 1

Answer: (A)

number of particle of the gas

$PV=nRT$

n = no. of moles

$PV=\left(N/N_A\right)\times RT$

Where $N=$ no. of molecules

$N_A=$ Avagadro number

$\therefore PV=NT\times \left(R/N_A\right)$

as $R/N_A=k_B=$ Boltzmann's constant

Hence $PV=N{k}_{B}T$

$\left(PV/k_{B}T\right)=N=$ no. of moecules