The quantity of electricity needed to liberate $0.5 g r a m$ equivalent of an element is

48250 f a r a d a y

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48250 c o u l o m b

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19300 f a r a d a y

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19300 c o u l o m b

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Solution

The correct option is C $48250 c o u l o m b$
Electricity required, $Q =$ No. of equiv. $\times$ 96500 coulombs

$= 0.5 \times 96500 = 48250 C$

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The quantity of electricity needed to liberate 0.5 gram equivalent of an element is

The correct option is C 48250 coulombElectricity required, Q= No. of equiv. × 96500 coulombs =0.5×96500=48250 C

The quantity of electricity needed to liberate $0.5 g r a m$ equivalent of an element is

The correct option is C $48250 c o u l o m b$
Electricity required, $Q =$ No. of equiv. $\times$ 96500 coulombs

$= 0.5 \times 96500 = 48250 C$