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Enthalpy of Neutralisation

The quantity ...

Question

The quantity of heat absorbed or evolved when 1 mole of an acid is neutralised by one mole of a base is called enthalpy of neutralisation.

A

True

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B

False

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Solution

The correct option is B False

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Q. Heat of neutralisation of an acid is the amount of heat evolved when one gram equivalent of the acid is neutralised by excess of the base. If true enter 1else 0.

1 g

equivalent of strong acid reacts with strong base heat released is

13.5 K c a l

1 g

H_{2} A

is completely neutralised against strong base

13 K c a l

is released. When

1 g

B (O H)_{2}

is completely neutralised against strong acid 10 Kcal heat is released. Calculate enthalpy change when 1 mole

H_{2} A

is completely neutralized by

B (O H)_{2}

.

Q. Given that, heat of neutralisation of strong acid and strong base is

57.1 k J

. Calculate the heat produced when

0.25

H C l

is neutralised with

0.25

N a O H

in aqueous solution:

Q. Enthalpy of neutralisation of acetic acid by

N a O H

- 50.6 k J m o l^{- 1}

Δ H

for ionisation of

C H_{3} C O O H

. Given, the heat of neutralisation of a strong acid with a strong base is

- 55.9 k J m o l^{- 1}

.

If $H^{+} + O H^{-} \to H_{2} O . Δ H = - 57.3 k J,$ then the heat of neutralisation for complete neutralisation of 1 mole $H_{2} S O_{4}$ by a base is:

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Enthalpy of Neutralisation

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