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Specific Heat Capacity

The quantity ...

Question

The quantity of heat given out by 'm' g of copper in cooling it from $t_{2}^{o} C$ to $t_{1}^{o} C$ is $m c (t_{2} - t_{1})$

True

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False

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Solution

The correct option is A True
We can calculate the heat released or absorbed using the specific heat capacity $C,$ the mass of the substance \text mmm, and the change in temperature $Δ T$ , T in the equation:
$q = m \times C \times Δ T, q = m \times C \times Δ T$
here temperature difference $= t_{2} - t_{1}$
$q = m c$ $t_{2} - t_{1}$

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(s p e c i f i c h e a t o f c o p p e r = 420 J k g^{- 1} K^{- 1}, s p e c i f i c h e a t o f w a t e r = 4200 J k g^{- 1} K^{- 1})

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