The quantity of heat needed to raise the temperature of 'M' g of water from $t_{1}^{o} C$ to $t_{2}^{o} C$ is $M C (t_{2} - t_{1})$

True

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

False

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A True
We can calculate the heat released or absorbed using the specific heat capacity $C,$ the mass of the substance \text mmm, and the change in temperature $Δ T$ , T in the equation:
$q = m \times C \times Δ T, q = m \times C \times Δ T$
here temperature difference $= t_{2} - t_{1}$
$q = M C$ $(t_{2} - t_{1})$
hence statement is correct

Suggest Corrections

Similar questions

t_{2}^{o} C

t_{1}^{o} C

m c (t_{2} - t_{1})

^{'} M^{'} g

t_{1}^{\circ} C

t_{2}^{\circ} C

x g

t_{1}^{o} C

y g

t_{2}^{o} C

t_{1}^{o} C

t_{2}^{o} C

1

1^{o}

Join BYJU'S Learning Program