The quantity of heat needed to raise the temperature of $^{'} M^{'} g$ of water from $t_{1}^{\circ} C$ to $t_{2}^{\circ} C$ is _____________.

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Solution

The quantity of heat needed of M g of water from $t_{1}^{o} C$ to $t_{2}^{o} C$ is $M s (t_{2} - t_{1})$ , where $s$ is the specific heat capacity of the water.

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Similar questions

t_{1}^{o} C

t_{2}^{o} C

M C (t_{2} - t_{1})

C p . m = 30.5

J K^{- 1} m o l^{- 1} + T (0.0102 J K^{- 2} m^{- 1})

^{\circ} C

^{\circ} C

T_{1}

= 100 + 273 = 373 K

T_{2}

= 500 + 273 = 773 K

1

1^{o}

1 gm

NTP

T_{1} K to T_{2} K

20 g

25^{o} C

500^{o} C

0.45 J K^{- 1}

g^{- 1}

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