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B
mass of a gas
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C
number of moles of a gas
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D
molar mass of a gas
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Solution
The correct option is C number of molecules in a gas PV=nRT n=no.ofmoles PV=(N/NA)×RT whereN=no.ofmolecules NA=Avogadro′snumber ∴PV=NT×(R/NA) asR/NA=KB=Boltzmann′sconstant hencePV=NKBT (PV/KBT)=N=no.ofmolecules