The quantity $\frac{p V}{k T}$ represents
(a) mass of the gas
(b) kinetic energy of the gas
(c) number of moles of the gas
(d) number of molecules in the gas.

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Solution

$Here, P V = n R T . . . (1) Also, k = \frac{R}{N} \Rightarrow R = k N . . . (2) Now, P V = n k N T [From eq . (1) and eq . (2)] \Rightarrow n N = \frac{P V}{k T} n N = Number of molecules \frac{P V}{k T} = Number of molecules$

Thus, (d) is the correct answer.

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The quantity pVkT represents (a) mass of the gas (b) kinetic energy of the gas (c) number of moles of the gas (d) number of molecules in the gas.

Here,PV=nRT ...1Also,k=RN⇒R=kN ...2Now,PV=nkNT From eq. 1 and eq. 2⇒nN=PVkTnN = Number of moleculesPVkT=Number of molecules Thus, (d) is the correct answer.

The quantity $\frac{p V}{k T}$ represents
(a) mass of the gas
(b) kinetic energy of the gas
(c) number of moles of the gas
(d) number of molecules in the gas.

$Here, P V = n R T . . . (1) Also, k = \frac{R}{N} \Rightarrow R = k N . . . (2) Now, P V = n k N T [From eq . (1) and eq . (2)] \Rightarrow n N = \frac{P V}{k T} n N = Number of molecules \frac{P V}{k T} = Number of molecules$

Thus, (d) is the correct answer.