The quantum numbers for the outermost electron of an element are given below as n -2- l -0- m -0- s -1-2 - The atoms isA- BerylliumB- HydrogenC- BoronD- Lithium

108

You visited us 108 times! Enjoying our articles? Unlock Full Access!

Molecular Orbital Energy Diagrams

The quantum n...

Question

The quantum numbers for the outermost electron of an element are given below as $n = 2, l = 0, m = 0, s = + \frac{1}{2}$ . The atoms is

Lithium

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Beryllium

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Hydrogen

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Boron

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

Suggest Corrections

Similar questions

The quantum numbers for an electron in the outermost orbital of an element are given as $n = 2, l = 0, m = 0, s = - \frac{1}{2}$ . The atom could be:

n

l

s = \frac{1}{2}

(i) n = 4, m_{s} = - \frac{1}{2}

(i i) n = 3, l = 0

(i i i) n = 2, l = 1

(i v) n = 2, l = 0

Join BYJU'S Learning Program