Question

The quantum numbers of six electrons are given below. Arrange them in order of increasing energies.

1. $n=4,l=2,m_1=-2,m_s=-1/2$
2. $n=3,l=2,m_1=1,m_s=+1/2$
3. $n=4,l=1,m_1=0,m_s=+1/2$
4. $n=3,l=2,m_1=-2,m_s=-1/2$
5. $n=3,l=1,m_1=-1,m_s=+1/2$
6. $n=4,l=1,m_1=0,m_s=+1/2$

Answer 1

1. The quantum numbers $n=4,l=2,m_1=-2,m_s=-1/2$ represents 4d orbital.

2. The quantum numbers$n=3,l=2,m_1=1,m_s=+1/2$ represents 3d orbital.

3. The quantum numbers$n=4,l=1,m_1=0,m_s=+1/2$ represents 4p orbital.

4. The quantum numbers$n=3,l=2,m_1=-2,m_s=-1/2$ represents 3d orbital.

5. The quantum numbers$n=3,l=1,m_1=-1,m_s=+1/2$ represents 3p orbital.

6. The quantum numbers$n=4,l=1,m_1=0,m_s=+1/2$ represents 4p orbital.

The order of increasing energies is $\left(v\right)<\left(ii\right)=\left(iv\right)<\left(vi\right)=\left(iii\right)<\left(i\right)$.