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Planck's Quantum Hypothesis

The quantum y...

Question

The quantum yield for decompostion of $H I$ is $0.2$ In a experiment $0.01 m o l e s$ of $H I$ are decomposed. Find the number of photons absorbed. $(N_{A} = 6 \times 10^{23})$

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Solution

As per avagadro hypothesis,
1 mole HI= $6.023 \times 10^{23}$ number of HI molecules
0.01 mole HI= $6.023 \times 10^{21}$ number of HI molecules
Quantum yield is defined as
$Q u a n t u m y i e l d = \frac{Molecules decomposed}{photons absorbed}$
$p h o t o n s a b s o r b e d = \frac{M o l e c u l e s d e c o m p o s e d}{Q u a n t u m y i e l d}$
$= \frac{6.023 \times 10^{21}}{0.2}$
$= 3.0115 \times 1 0^{22}$

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