The quotient and remainder when $3 x^{4} + 6 x^{3} - 6 x^{2} + 2 x - 7$ is divided by $x - 3$ are

Quotient:

3 x^{3} + 15 x^{2} + 39 x + 119

and Remainder:

350

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Quotient:

3 x^{3} + 10 x^{2} + 39 x + 119

and Remainder:

35

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Quotient:

3 x^{3} + 15 x^{2} + 39 x + 119

and Remainder:

50

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Quotient:

3 x^{3} + 15 x^{2} + 119

and Remainder:

350

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A Quotient: $3 x^{3} + 15 x^{2} + 39 x + 119$ and Remainder: $350$
Division of $3 x^{4} + 6 x^{3} - 6 x^{2} + 2 x - 7$ by $x - 3$ is shown by the image
So, we get Quotient $= 3 x^{3} + 15 x^{2} + 39 x + 119$ and Remainder $= 350$
Hence, option A is correct.

Suggest Corrections

Similar questions

Write the quotient and remainder when we divide.

$(15 x^{2} + x - 6)$ by $(3 x + 2)$

3 x^{3} - 8 x^{2} + x + 7

x - 3

(7 x^{2} + x + 5)

(3 x^{3} - 2 x^{2} + 7 x - 5) \div (x + 3)

({2 x}^{4} + {3 x}^{3} + 4 x - 2) \div (x + 2)

Join BYJU'S Learning Program