The quotient obtained by dividing $34 y^{5}$ by $7 y$ is .

\frac{7}{34} y^{2}

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\frac{34}{7} y^{4}

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\frac{7}{34} y

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\frac{7}{34} y^{3}

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Solution

The correct option is B $\frac{34}{7} y^{4}$
$34 y^{5}$ by 7y
$\frac{34 y^{5}}{7 y} = \frac{34}{7} y^{4}$

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