The quotient obtained when pq2+5pq+6p is divided by pq+2p is _______.
q + 3
Let's first factorise the numerator of the given expression by using the method of common factors.
pq2+5pq+6p
= p×q×q+5×p×q+6×p
= p(q2+5q+6)
Now, factorize q2+5q+6 by using identities.
Note that 2+3=5 and 2×3=6
So, q2+5q+6=(q+2)(q+3)
[q2+5q+6=q2+2q+3q+6
=q(q+2)+3(q+2)
=(q+2)(q+3)]
So, p(q2+5pq+6p)=p(q+2)(q+3)
∴pq2+5pq+6ppq+2p=p(q+2)(q+3)p(q+2) =q+3