The correct option is A q+3
First factorize the given expression by using the method of common factors.
pq2+5pq+6p=p×q×q+5×p×q+6×p
=p(q2+5q+6)
Now, factorize q2+5q+6 by using identities.
In q2+5q+6, 6=2×3 and 2+3=5
So, q2+5q+6
=q2+2q+3q+6
=q(q+2)+3(q+2)
=(q+2)(q+3)
So, p(q2+5pq+6p)=p(q+2)(q+3)
Now, p(q+2)(q+3)p(q+2)=q+3